習題31 - 做出決定

這次是透過input語句, 來讓if, elif & else 去做判斷.
並不難.
要小心是分段!! 如果有多層次的判斷分支,
記得要TAB的空格一致

用Notepad++打下列的程式碼,
另存為ex31.py. 我附上中文注釋方便好讀.

print("""You enter a dark room with two doors.
Do you go through door #1 or door #2?""")

# 由input 輸入, 讓後面的語句來判斷,
door = input ("> ")

# 如果輸入為1, 就再執行一次選擇
if door == "1":
    print("There's a giant bear here eating a cheese cake.")
    print("What do you do?")
    print("1. Take the cake.")
    print("2. Scream at the dear")

# 再由input 輸入, 讓後面的語句來判斷,
    bear = input("> ")
# 這行是1.1的判斷結果
    if bear == "1":
        print("The bear eats your face off, Good job!")
# 這行是1.2的判斷結果
    elif bear == "2":
        print("The bear eats yours legs off, Good job!")
# 這行是1.x的判斷結果
    else:
        print(f"Well, doing {bear} is probably better.")
        print("Bear run away.")

# 如果輸入為2, 就再執行另一次選擇
elif door == "2":
    print("You stare into the endless abyss at Cthulhu's retina.")
    print("1. Blueberries.")
    print("2. Yellow jacket clothespins.")
    print("3. Understanding revolvers yelling melodies.")

# 再由input 輸入, 讓後面的語句來判斷
    insanity = input("> ")

# 這行是2.1 & 2.2的判斷結果
    if insanity == "1" or insanity == "2":
        print("Your body survives powered by a mind of jello.")
        print("Good job")
# 這行是2.x的判斷結果
    else:
        print("The insanity rots your eyes into a pool of muck.")
        print("Good job!")
#這行是1.x & 2.x 都沒選的判斷結果.
else:
    print("You stumble around and fall on a knife and die. Good job!")

然後用Windows的cmd, 執行python.

C:\Windows\System32>cd C:\Users\Peter\Desktop\Python\LP3THW
C:\Users\Peter\Desktop\Python\LP3THW>python ex31.py
You enter a dark room with two doors.
Do you go through door #1 or door #2?
> 1
There's a giant bear here eating a cheese cake.
What do you do?
1. Take the cake.
2. Scream at the dear
> 1
The bear eats your face off, Good job!

C:\Users\Peter\Desktop\Python\LP3THW>

完成


最初發表 / 最後更新: 2018.09.09 / 2018.09.09